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12x^2-1+9x=0
a = 12; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·12·(-1)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{129}}{2*12}=\frac{-9-\sqrt{129}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{129}}{2*12}=\frac{-9+\sqrt{129}}{24} $
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